Sunday, November 27, 2005

How many candies filled the jar?

Good afternoon jellybeans!

And now, the number you have all been waiting for... [drumroll please]...

x(7x^3+3x^2+5) where x=3

...so close to the truth! Who will accept this challenge? :0)

I learned a lot from teaching both classes on Friday especially that the last period on a Friday afternoon is one of the most difficult to manage because students seem to be high energy, excited about the weekend, and teachers seem to be low energy after a long week of hard work. I'm open to some suggestions as to how to make next Friday work.

Hope you all had a great weekend, and I look forward to exploring "statistics" with you more over the next four weeks.

4 Comments:

At 7:07 PM, Blogger Arvin A. said...

i accept this challenge...

x(7x^3+3x^2+5) where x=3

is equivalent to...

......243......

if i am wrong.. MY BAD!!!
lol.... take care all... cya tomorow!!!!

[008]-iced tea addict-[008]

 
At 7:39 PM, Blogger Daureen N. said...

hmmm...
let me try it...

x(7x^3+3x^2+5)
3(7(3)(3)(3)+3(3)(3)+5)
3(7(27)+ 3(9)+5)
3(189 + 27 + 5)
3(221)

=663 candies in the jar??
... i dont know if its right..oh well ..

did i even do it right ?

can someone check my answer if its right or not .. pls and thank u !

Later ..

 
At 7:47 PM, Blogger Arvin A. said...

NOOOOO IM WRONG!!! i checked daureens and it's right..
i made a mistake on the 7x^3
i sed it was 49 for some reason...
maybe i added it..
oh well..
"even the greatest minds make mistakes"
-anonymous

im not a great mind.... and i made a mistake...hahahahahaha

GREAT WORK DAUREEN!!!!!!

 
At 11:51 PM, Blogger Ryan R.(rayan) said...

I will try this challenge...but I am going to sleep cause im tired...so i will do it tomorrow...XD

 

Post a Comment

<< Home